[Discretefall11] Section 5.1 (Hints for 16a,c)

[Andreas Kloeckner]

Hi Ezra,

On Sat, 26 Nov 2011 15:54:11 -0500, Ezra B Schrage <ebs295 at nyu.edu> wrote:
> I was doing the homework for section 5.1 and I was looking at problem 16.
> Perhaps it's just my algebra being rusty, but I'm having trouble figuring
> out how to organize the factors by 2^2 * 3 * 5^2 for part a and 2^3 * 3 ^2
> * 7 * 18 for part c. I can figure out the factors by systematically going
> up, but it escapes me with how to organize the separate the columns by
> these factors. I apologize if there's some extraordinarily simple solution
> for this. Hope your holiday is going well.

please send such questions to the list first--maybe one of your
classmates is able to help you more quickly than I'll be able to, or
perhaps somebody else has the same question as you. Also please state in
the subject line what problem you're asking about to avoid inadvertent
spoilers.

Regarding 16a, observe that each factor of 300 can be built as

 2^i * 3^j * 5^k
 
with

 i in {0,1,2}
 j in {0,1}
 k in {0,1,2}
 
3*2*3 = 18

HTH,
Andreas

-- 
Andreas Kloeckner 
Room 1105A (Warren Weaver Hall), Courant Institute, NYU
http://www.cims.nyu.edu/~kloeckner/
+1-401-648-0599
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